50 two rupees coins are places one above the
ther to form a right circular cylinder. If each
in has radius 1.4 cm and thickness 0.3 cm,
find its total surface area
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0
Answer:
16.66
Step-by-step explanation:
Surface area of a cylinder = πr^2+πr'2+2πrh=2πr[r+h]
=(22/7×1.4×1.4)+2×22/7×1.4+1.4+0.3
=6.16+8.8+1.4+0.3
=16.66
The answer is 16.66cm
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