Question

50 watt bulb emits monocromatic light of wavelength of 500 A. calculate the rate of emmision of quanta per second.​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The energy of one photon is

E= λhc

​

= 0.57×10 −6

6.626×10 −34 Js×3×10

8m/s

​

=3.487×10

−19 J .

25 watt corresponds to 25 J per second.

The number of photons emitted per second is

3.487×10 −19

25

=7.17×10 19 /s.

Explanation:

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