Question

ꜰɪɴᴅ ᴛʜᴇ ᴀᴠᴇʀᴀɢᴇ ꜰʀɪᴄᴛɪᴏɴᴀʟ ꜰᴏʀᴄᴇ ᴛʜᴀᴛ ᴡᴏᴜʟᴅ ꜱᴛᴏᴘ ᴀ ᴄᴀʀ ᴏꜰ ᴡᴇɪɢʜᴛ 500ᴋɢ. ɪɴ ᴀ ᴅɪꜱᴛᴀɴᴄᴇ ᴏꜰ 25ᴍ ɪᴛꜱ ɪɴᴛɪᴀʟ ꜱᴘᴇᴇᴅ ɪꜱ 20ᴍ/ꜱ
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Answer 1

Answer:

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Explanation:

Height of object (h) = 3cm

Focal length ( f ) = 10cm

Distance of object from lens (u) = - 15cm

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Answer 2

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Given -

Weight of car = 500 kg

Distance = 25 m

Speed = 20 m/s

To Find -

The average frictional force

Solution -

= 72×518 [Changing into m/s]

= 20 m/s.

Distance covered by it = 25 m.

{v}^{2} - {v}^{2} = 2asv

2

−v

2

=2as

= 0 - (20) ^{2} = 2(a)(25)=0−(20)

2

=2(a)(25)

= - 400 = 50 \times a=−400=50×a

a = - 8a=−8

Now, Frictional Force = m × a

= 500×−8

= - 4000 N.

Here, negative sign shows the force is acting in the opposite direction of the displacement.

∴ Frictional force is 4000 N.

Thank You

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