500 children were having lunch in a school hall. Out of these, 180 choose to have sandwich in
their lunch.
a) What fraction of the children choose sandwich?
b) What percentage of the children choose sandwich?
c) What percentage of the children did not choose sandwich?
7.Arun score 70 out of 80 in maths paper and Seema score 80 out of 90 in science paper.
Who scored more of the two?
Answers
Answered by
31
Answer:
Total children= 500
Number of children having sandwich= 180
Number of children not having sandwich= 500-180 = 320
a) Fraction of children who choose sandwich= 180/500= 9/25
b) Percentage of children who choose sandwich= (180/500)* 100 = 36%
c) Percentage of children who did not choose sandwich = 100-36 = 64%
7. To find who scored more, we can find the percentage marks obtained in both the cases
Percentage marks obtained by Arun= (70/80)*100 = 700/8 = 87.5%
Percentage marks obtained by Seema= (80/90)*100 = 800/9 = 88.89%
Hence, Seema scored more out of the two.
Answered by
17
Answer:
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step by step explanation:
total children=500
no of children having=180
no of children not having sandwhich=500-180=320
a)fraction of children who choose sandwhich=180/500=0.36//
b)% of children who choose sandwhich=0.36×100=36%
c)% of children who did not choose sandwhich =100-36=64%
7. To find, who scored more, let's find the % marks obtained by arun and seema.
©%mark obtained by arun=(70/80)×100=87.5%
©%mark obtained by seema=(80/90)×100=88.89%.
HENCE SEEMA SCORED MORE THAN ARUN..
HOPE IT'S HELPED U....LUV U..
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