500 g of an arurea solution of mole traction 0.2 is diluted to 1500 g the mole fraction of solute in the diluted solution is
Answers
Answered by
1
500gm of urea solution of mole fraction 0.2 is diluted to 1500 gm. calculate the mole fraction of solute in the diluted solution
Ask for details Follow Report by Balkaran6493 13.07.2018
Answers
Me · Beginner
Know the answer? Add it here!
tiwaavi
tiwaavi Genius
Mass of the Urea solution = 500 grams.
Molar mass of the Urea = 60 g/mole.
Mole Fraction of the Urea in a Original Solution = 0.2
This means that 0.2 mole of Urea is 1 mole solution.
∴ Mass of the Urea in a solution of 500 g = 0.2 × 60 g/mole.
= 12 g.
∴ Mass of the water = 500 - 12
= 488 g.
Similar questions
English,
7 months ago
Math,
7 months ago
English,
7 months ago
Computer Science,
1 year ago
Biology,
1 year ago
Computer Science,
1 year ago
Science,
1 year ago