500 g of water and 100 g of ice at 0*c are in a calorimeter whose water equivalent is 40 g. 10 g of steam at 100*c is added to it.Then water in the calorimeter is
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energy released by the condensation of vapour is not sufficient to melt the whole ice
...
So, the amount of energy released by the water vapour, when it condensed and comes to 00C
E=m vapourL vapour+m vapourS vapour×100
⇒E=10×540+10×1×100
⇒E=6400 cal
So, let m mass of the ice is m'....
m'Lice=6400
⇒m'=640080
⇒m'=80 gm
total amount of water in the capillary tube is
m0=500+80+10
⇒m0=590 gm
thank you.. ☺
♪\(*^▽^*)/\(*^▽^*)/
energy released by the condensation of vapour is not sufficient to melt the whole ice
...
So, the amount of energy released by the water vapour, when it condensed and comes to 00C
E=m vapourL vapour+m vapourS vapour×100
⇒E=10×540+10×1×100
⇒E=6400 cal
So, let m mass of the ice is m'....
m'Lice=6400
⇒m'=640080
⇒m'=80 gm
total amount of water in the capillary tube is
m0=500+80+10
⇒m0=590 gm
thank you.. ☺
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