Question

500 logs are stacked in a way such that 32 logs in the bottom row, 31 in the next row, 30 in the row next to it and so on. In how many rows are the 500 logs placed and how many logs are in the top row?

Answer 1

Answer:

25 OR 40

Step-by-step explanation:

32,31,30,..........

an=a+(n-1)d

  =32+(n-1)-1

 =32-n+1

=33-n     -------1

sn=n/2(a+an)

500=n/2(32+33-n)   from 1

500=n/2(65-n)

2(500)=n(65-n)

1000=65n-n2

- (-n2+65n-1000=0)

n2-65n+1000=0

n2-40n-25n+1000=0

n(n-40)-25(n-40)=0

(n-25)(n-40)=0

n=25, n=40

the number of logs on the top maybe 25 or 40.

Answer 2

Answer:

25 or 40

Step-by-step explanation:

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