Question

500 ml of 0.2 m boh is mixed with 500 ml .1 m hcl kb is what

Answer 1

Hydroxide ion releases from 500 ml of 0.2 M boh as:

n = M V

= 0.2 (500) = 100 m mol

Protons releases from 500 ml 0.1 m HCl

n = M V

= 0.1 (500) = 50 m mol

Hydroxide ion concentration left = 100 -50 = 50 m mol

Concentration of hydroxide = n /V

= 50 /1000 = 0.05 M

pOH = - log (OH)

= - log (0.05) = 1.53

As, pH + pOH = 14

pH + 1.53 = 14

pH = 12.47

Hence, pH of 500 ml of 0.2 m boh is mixed with 500 ml .1 m hcl is 12.47

Answer 2

Answer:

ph is 5

Explanation:

Here this question is asking us to find the ph of BCl during salt hydrolysis.

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