Question

500 mL of 0.2 M NaCl sol, is added to 100 mL of 0.5 M AgNO, solution resulting in the formation of white precipitate of
AgCI. How many moles and how many grams of AgCl are formed ? Which is the limiting reagent?​

Answer 1

Answer:

solution added is 500mL

Then the equation is

Nacl+$AgNO_{3}$⇒$NaNO_{3} +Agcl$

                                                                      (Yellow)

Then

=0.2*$\frac{500}{100}$

=0.1mol

And

$\frac{100}{1000} *0.5$

=0.05 mol

$AgNO_{3}$ is present more than required so Nacl is the limiting solution.