500 ML of 0.2 molal naoh solution is required to utilize 500 ml of X-M h2so4 solution. then find the value of x
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Molarity (M) : The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.
Molarity of a solution
(M)=molar mass of solutemass of solute×volume of solution in mL1000
∴0.2=40w×5001000
so w=4gm.
Amount of sodium hydroxide present in 500ml of 0.2M solutions is 4 gm.
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