Question

500 ml of 1m solution of glucose is mixed with 500ml of 1m of glucose find molarity

Answer 1

since the sol. contains 6.02 x 10^22 molecules, 
the no. of moles of glucose = 6.02 x10^22 / N(avogadro) 
                                         = 6.02 x 10^22 /6.022 x 10^23
                                         = 0.1 moles (approx.)
volume of solution = 500 ml. = 0.5 L
therefore, concentration of solution in terms of molarity (since they haven’t specified a method, molarity is the quickest form to express in, in this case) 
molarity = no. of moles of solute / volume of solution( in litres)
             = 0.1 / 0.5 
            = 0.2 M 

Answer 2

Hey there!

• n = 6.023*10²² / 6.023*10²³

• n = 0.1 mole

• Volume of glucose = 500 mL = 0.5 L

• Molarity, M = n/V = 0.1/0.5 = 0.2.