Question

500 ml of a gaseous hydrocarbon when burnt in excess of o2 gave 2.5 lit of co2 and 3 lit of h2o under same conditions. molecular formula of the hydrocarbon is

Answer 1

Hey dear,

● Answer -
C5H12 (Pentane)

● Explaination -
For n litrres of hydrocarbon, combustion reaction is shown by -
n CxHy + n(x+0.25y) O2 ---> nx CO2 + 0.5ny H2O

When 0.5 L of hydrocarbon is burnt,
CO2 evolved = 0.5 × x
2.5 = x / 2
x = 5
H20 formed = 0.5 × 0.5 × y
3 = y / 4
y = 12

Therefore, formula of the hydrocarbon compound is C5H12 (Pentane).

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