Question

500 ml of NaOH solution has a density of 1.1 g/ml and is 20% by weight NaOH. Calculate
the molality of the solution​

Answer 1

Answer:

umynnbh bf jb gf gv

Explanation:

nyynyng gtin

Answer 2

Explanation:

Let x be the mass of solution.

Mass of NaOH=

100x×20

Molar mass of NaOH=40g

∴ Number of moles= ( 10020x )/40= 200x

Now mass of solvent in the solution= x− 100

20x = 10080x

∴ Molality= (80x/100)x/200×1000=6.25M