Math, asked by b4bhist, 10 months ago

500 people standing in a circle in an order 1 to 500. No. 1 has a sword. He kills the next person (i.e. No. 2) and gives the sword to the next (i.e. No. 3). All people do the same until only 1 survives. Which number survives at the last?
There are 500 people starting from 1 to 500.

Answers

Answered by lavish2709yadav
2

Answer:489th man will survive only.

Step-by-step explanation:

In this puzzle,

Step 1:

Find the lowest power of 2 > n

Where n is given number of people =500

2^9=512 Let's call it P

Step 2 :

Subtract n from (P-1). Lets call it Q,

Q = (P-1)- n , as: Q= (512 -1) - 500 =11

Step 3 :

Multiply Q by 2. as: 11×2 =22

Step 4 :

Subtract Q×2 from P-1 and you will find the person with number “ans” will survive till last.

as: (512 - 1) - 11×2

=511-22= 489 = ans.

Answered by minku8906
0

Only the 489th man will live.

We solve the following by these steps:

Step 1: Determine the lowest power of 2 > n, where n is the number of persons =500 291=512. Let's call it P for short.

Step 2: Subtract n from the total (P-1). Let's call it Q, and define it as Q = (P-1)-n, as in Q= (512 -1) - 500 =11.

Step 3: Multiply Q by 2 (e.g 112 = 22).

Step 4: Then you subtract Q2 from P-1, and you'll notice that the individual with the number will be the last one standing.

Hence the answer comes as :  (512 - 1) - 112 =511-22 = 489

#SPJ2

Similar questions