Question

500 persons are taking a dip into a cuboidal pond which is 80m long and 50m broad.
What is the rise of water level in the pond, if the average displacement of the water by
a person is 0.04m3​

Answer 1

Answer:

Let 'h' be the rise in the level of water in the tank.

Now,

The amount of water rises in the tank = Displacement of water taken by 500 persons.

That is:

$\implies$ Length × Breadth × Height

But we have:

$\implies$ 20 $\sf{m^{3}}$ = 80 m × 50 m × h

And:

Let us find the rise of water level in the pond, so:

$\implies$ $\sf{h=\frac{20}{80 \times 50}}$

$\implies$ $\sf{h=\frac{20}{4000}}$

$\implies$ $\sf{h=\frac{1}{200}\:m}$

$\implies$ $\sf{h=0.5\:cm}$

Thus,

The rise of level of water in the tank: 5 mm

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Answered by: Niki Swar, Goa❤️

Answer 2

Answer:

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