Math, asked by vashokkumarr, 9 months ago

500 persons are taking a dip into a cuboidal pond which is 80m long and 50m broad.what is the rise of water level in the pond,if the average displacement of the water by person is 0.04mcube...

Answers

Answered by rishabh9987
1

Step-by-step explanation:

Displacement of water by 500 persons :

= 500 × 0.04

= 20m³

Displacement of water = Rise in volume of water in the pond.

20 m³ = 80 × 50 × h

h = 20/80 × 50

= 20 /4000

= 1/200 m

= 0.5 cm

So, The rise of water level in pond = 0.5 cm

Hope it is helpful to you.

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Attachments:
Answered by nilesh102
2

\textbf{\huge\underline{\underline\red{solution} : -  }} \\  \\ \bold{\underline\purple{here \: we \: know}} \\  \\  \red{1.} \bold \blue{ \: length  \: (l)\: of \: cuboidal \: \: tank \: is \: 80 \: m .} \\ \red{2.} \bold \blue{ \: breadth  \:( b)\: of \: cuboidal \: tank \: is \: 50 \: m.} \\ \red{3.} \bold \blue{ \: displacement \: of \: water \: by \: a \: one \: } \\  \bold \blue{person \: in \: a \: tank \: is \:0.04 \:  {m}^{3} .} \\  \\ \underline \bold\red{so \:  \:displacement \: of \: water \: in \: a \: tank \: by \:} \\ \underline \bold\red{ 500 \: persons  }  =  \blue{500 \times0.04 = 20\: }\bold\blue{ {m}^{3}  \:  \:  \:  \: ..(1)} \\  \\  \underline \bold \purple{let \: height \: of \: cuboidal \: tank \: is \: h} \\  \\ \underline\bold\blue{to \: find \: volume \: of \: water \: in \: tank} \\  \\ \underline \bold \red{volume\: of \: cuboidal \: tank \: } =  \bold \purple{ l\times  b\times h} \\  \\  \bold \red{v.o.c.t} =  \bold \purple{80 \times 50 \times h} \\  \\ \bold \red{v.o.c.t} =  \bold \purple{(4000 \times h \: \: )  {m}^{3} \:  \:  \: ..(2) } \\  \\    \underline\bold\blue{as \: we\: know} \\  \\  \underline\bold\purple{volume \: of \: raised \: water \: in \: cuboidal } \\ \underline\bold\purple{tank \: is \: equal \: to \: displacement \: of \: water \: in } \\ \underline\bold\purple{ tank\: by \:500 \: person .} \\  \\ \underline\bold\red{hence} \\  \\ \bold\red{volume \: of \: raised \: water \: in \: cuboidal} \\\bold\red{tank \:}  = \bold\purple{ displacement \: of \: water \: in } \\ \bold\purple{ tank\: by \:500 \: person .} \\  \\   =  > \bold \blue{4000 \times h} = \bold \blue{20} \\  \\  =  > \bold \blue{h} = \bold \blue{ \frac{20}{4000}} = \bold \blue{ \frac{1}{200} } = \bold \blue{0.005 \: m} \\  \\   \underline \bold\red{Hence   \: \purple{0.005 \: m} \: level \: of \: water \: rise \: in \: tank.}

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