Question

500 persons are taking a dip into a cuboidal pond which is 80 m long and 50 mbroad. whatis the rise of water level in the pond, if the average displacement ofthe water by a person is0.04m3?

Answer 1

Hello friends


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Let write the given values:

Length of the pond (l) = 80 m

Breadth of pond (b) = 50 m

Now, we will calculate the volume for the rise of water level in the pond

We know that,

Volume of cuboid = l x b x

Now put the given values,

volume of the water level in the pond wil be.

= 80 x 50 x h

= 400hm^3

We know that the average Displacement of the water by a person = 0.04 m^2

Hence, the average Displacement of the water by whole person means by 500 person will be,

= 0.04 x 500 m^3

By the given statements,we can understand that,

Volume of the rise of water level in the pond = average Displacement of the water by 500 persons.

by applying the statement we get,

===>>
$400h = 500 \times 0.04 \\ \\ h = \frac{500 \times 0.04}{4000} \\ \\ h = \frac{20}{4000} \\ \\ h = \frac{1}{200} m \\ \\ h = 0.005m$

Now we will convert it into centimeter

So we know that 1m = 100 cm

==> 0.005 x 100 cm

==> 0.5 cm

Therefore, the rise of the water level in the pond is 0.5 cm.


THANKS,,,,,,

:)

Answer 2

Hope it will help u ...☺