Question

500 persons are taking dip into a cuboidal pond which is 80m long and 50m broad.What is a rise of water level in the pond if average displacement of water by a person is 0.04m3?​

Answer 1

Step-by-step explanation

:Suppose level of water rises by h meters in the pond.

Then,

Clearly,

Water rises in the pond forms a cuboidal of dimensions

$80m \times 80m \times h \: m.$

$80 \times 50 \times h = volume \: of \: water \: displaced \: by \: 500 \: persons \\ 80 \times 50 \times h = 500 \times 0.04 \\ 4000h = 20 \\ h = \frac{1}{200} \\ h = 0.5cm$

Therefore,

The level of rise of water is 0.5cm.

Hope

Answer 2

Answer:

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Step by step explanation:-

_________________________

Given:-

___________

pond dimensions:-

long=80m

broad=50m

To find :-

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Height =?

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from the observation we can clearly see that ,its forms a Cuboid .

So ,

80 x 50 x h = volume of water displaced

4000x h = 500 x 0.04

h = 1/200

h = 0.5 cm

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Hence we get this answer;)

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