Question

500 persons have to dip in a rectangular tank which is 80 m long and 50 m broad. What is the rise in the level of water in the tank, if the average displacement of water by a person is 0.04 m³?

Answer 1

Answer:

The rise in water level of the rectangular tank is 0.005 m  = 0.5 cm  

Step-by-step explanation:

Given :  

Number of persons to dip in a rectangular tank = 500  

Length of a rectangular tank (l) = 80 m

Breadth of the rectangular tank (b) = 50 m

Average displacement of water by 1 person = 0.04 m³

Volume of water displaced by 500 persons = 500 × 0.04 = 20 m³ ………….(1)

Let ‘h’ m  be the height of the raised water .

Volume of the rectangular tank = length × breadth ×  height = lbh

= 80 × 50 × h m³ = 4000h m…… ……….(2)

Volume of the raised water in the rectangular tank  is equal to  the volume of water displaced by 500 persons.

Volume of the rectangular tank = Volume of water displaced by 500 persons  

4000h = 20 m³

[From eq 1 & 2]  

h = 20/4000 = 1/200 = 0.005 m  = 0.5 cm  

h = 0.005 m  = 0.5 cm  

Hence, The rise in water level of the rectangular tank is 0.005 m  = 0.5 cm  

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

HÈLLØ!!

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$\Huge{\mathfrak{\green{\underline{ANSWER}}}}$

✔️The volume of one person = 0.04 m³ ,

be cause when the person takes a dip in the tank, the amount of water displaced is equal to the volume of the person.

✔️500 people take dip at the same time, then water displaced

= 500 × 0.04

= 20 m³

✔️the water rises inside the tank of the area of 80 m × 50 m

= 4000 m².

✔️The height to which water rises

= volume / area

= 20/ 4000

= 1/200 m

=0.005 m

= 5 millimeters

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THÅÑKẞ!!