500 persons have to dip in a rectangular tank which is 80 m long and 50 m broad. What is the rise in the level of water in the tank, if the average displacement of water by a person is 0.04 m³?
Answers
Answer:
The rise in water level of the rectangular tank is 0.005 m = 0.5 cm
Step-by-step explanation:
Given :
Number of persons to dip in a rectangular tank = 500
Length of a rectangular tank (l) = 80 m
Breadth of the rectangular tank (b) = 50 m
Average displacement of water by 1 person = 0.04 m³
Volume of water displaced by 500 persons = 500 × 0.04 = 20 m³ ………….(1)
Let ‘h’ m be the height of the raised water .
Volume of the rectangular tank = length × breadth × height = lbh
= 80 × 50 × h m³ = 4000h m…… ……….(2)
Volume of the raised water in the rectangular tank is equal to the volume of water displaced by 500 persons.
Volume of the rectangular tank = Volume of water displaced by 500 persons
4000h = 20 m³
[From eq 1 & 2]
h = 20/4000 = 1/200 = 0.005 m = 0.5 cm
h = 0.005 m = 0.5 cm
Hence, The rise in water level of the rectangular tank is 0.005 m = 0.5 cm
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HÈLLØ!!
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✔️The volume of one person = 0.04 m³ ,
be cause when the person takes a dip in the tank, the amount of water displaced is equal to the volume of the person.
✔️500 people take dip at the same time, then water displaced
= 500 × 0.04
= 20 m³
✔️the water rises inside the tank of the area of 80 m × 50 m
= 4000 m².
✔️The height to which water rises
= volume / area
= 20/ 4000
= 1/200 m
=0.005 m
= 5 millimeters
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THÅÑKẞ!!