Question

500 persons took a dip in a rectangular tank which is 80m long and 50m broad . What is the rise in level of water in the tank , if the average displacement of water by a person is 0.04m³

Answer 1

vol of water diplaced by one person = 0.o4m^3
vol of water displaced by 500 persons = 500*4/100 = 20 m^3

lenght of tank= 80 m
breadth of tank 50 m

height of water displaced = h
now vol of water displaced = 80*50*h

A.T.Q

80*50* h = 20

h=1/200m=0.5 cm

Answer 2

Answer:

The rise in water level of the rectangular tank is 50 m  = 0.5 cm  

Step-by-step explanation:

Given :  

Number of persons to dip in a rectangular tank = 500  

Length of a rectangular tank (l) = 80 m

Breadth of the rectangular tank (b) = 50 m

Average displacement of water by 1 person = 0.04 m³

Volume of water displaced by 500 persons = 500 × 0.04 = 20 m³ ………….(1)

Let ‘h’ m  be the height of the raised water .

Volume of the rectangular tank = length × breadth ×  height = lbh

= 80 × 50 × h m³ = 4000h m…… ……….(2)

Volume of the raised water in the rectangular tank  is equal to  the volume of water displaced by 500 persons.

Volume of the rectangular tank = Volume of water displaced by 500 persons  

4000h = 20 m³

[From eq 1 & 2]  

h = 20/4000 = 1/200 = 0.005 m  = 0.5 cm  

h = 0.005 m  = 0.5 cm  

Hence, The rise in water level of the rectangular tank is 0.005 m  = 0.5 cm  

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