5000 cal of heat is supplied to 1 litre of water. Find the rise in temperature of water.Given specific heat capacity of = 1 cal/g degree Celsius. Density of water = 1g/c
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Answer:
Volume=1lt=10^3cc
mass=density * volume=1 *10^3=10^3gm
According to qs,
5000=10^3*1*Δt
Δt=5 C
Explanation:
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