5000cal of heat is supplied 1L of water.Find the rise in temperature of water .Give specific heat capacity - 1 cal/g°C . Density of water - 1 g/cc.
Answers
Answered by
1
Answer:Volume=1lt=10^3cc
mass=density * volume=1 *10^3=10^3gm
According to qs,
5000=10^3*1*Δt
Δt=5 C
Explanation:
Similar questions