Physics, asked by devesh284460, 5 months ago

5000cal of heat is supplied 1L of water.Find the rise in temperature of water .Give specific heat capacity - 1 cal/g°C . Density of water - 1 g/cc.​

Answers

Answered by Anonymous
1

Answer:Volume=1lt=10^3cc

mass=density * volume=1 *10^3=10^3gm

According to qs,

5000=10^3*1*Δt

Δt=5 C

Explanation:

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