Question

5000J of work would done to carry how much charge between two pionts having potential difference of 100V

Answer 1

Answer:

50 C

Explanation:

Given :

Work done = 5000 J

Potential difference = 100 V

We are asked to find Charge.

We know :

Potential difference = Work done / Charge

= > Charge = Work done / Potential difference

i.e. Q = W / V

Putting values here we get :

= > Charge = 5000 J / 100 V

= > Charge = 50 C

Therefore , we get required answer.

Answer 2

Answer:

5000J of work done to carry the charge 50Coloumbs between two points has a potential difference 100Volts.

Explanation:  

Given

Work done W = 5000J

Potential difference = 100V

we need to find the charge carried between the two points.

Work done:

Work done(W) in an electric field between two points can be defined as the product of the charge(q) between two points and the potential difference(V) between two points.

                       W = Vx q

                   ⇒ q = W/V

Since, W = 5000Joules and V = 100Volts

         Substitute the values in the above equation

                      q = 5000/100

                      q = 50Coloumbs

Hence, the charge carried between two points = 50Coloumbs

Know more about Energy:

brainly.in/question/6823920?referrer=searchResults