Question

500g of water at 60℃ is contained in a vessel of negligible heat capacity.Into this water is added 400g of ice at 0℃.Calculated the amount of ice which does not melt.​

Answer 1

Given :-

Mass of water = m = 500 g

SHC of water = c = 4.2 Jg-¹°C-¹

SLH of ice = L = 336 Jg-¹

As we know that,

Heat lost by 500 g water at 60°C,

H = mc(T-0)

H = 500 × 4.2 × 60

Again,

Heat lost in melting m gram of ice at 0°C

mL = H

m × 336 = 500 × 4.2 × 60

m = 30000 × 4.2/336

m = 375 g

Hence,

Amount of ice which doesn't melt = 400 - 375 = 25 g.

Answer......