Question

500kg water is stored in the over head tank of a 10m high bulding. calculatethe amount of potential energy stored in the water? ​

Answer 1

Answer:

potential \: energy = mghpotentialenergy=mgh

so using this formula m=500kg g=9.8mps h=10m

so PE =500×10×9.8=49000

Answer 2

Explanation:

PE = mgh ( g= 10m/s2)

= 500x10x10 = 50000J

if taking (g=9.8m/s2)

PE= 49000J