Question

500mL of 1M HCl solution mixed with 300mL of 0.5M HCl solution.The molarity of the resulting solution will be
(1) 0.7 M
(2) 0.8 M
(3) 0.9 M
(4) 1.2 M​

Answer 1

Answer:

$\scriptsize{M_1V_1 + M_2V_2 = M_R(V_1 + V_2)}$

$\scriptsize{where \: M_R = resultant \: molarity \: of \: the \: mixture.}$

$\scriptsize1 \times 500 + 0.5 \times 300 = M_R(500 + 300)$

$500 + 150 = M_R(800)$

$650 = M_R(800)$

$\frac{65 \cancel0}{80 \cancel0} = M_R$

$\frac{65 }{80 } = M_R$

$M_R = 0.8125$

$or \: \: \: \: M_R = 0.8M$

Answer 2

Hope this helps you