503 term of sequence 9 13 17 21
Answers
Answered by
12
Here the sequence is in AP series
Here a=9 ,d=4 and n=503
and formula apply a +(n-1) ×d
=9 + (503 - 1 ) ×4
=9+502×4
=9+2008
=2017
Here a=9 ,d=4 and n=503
and formula apply a +(n-1) ×d
=9 + (503 - 1 ) ×4
=9+502×4
=9+2008
=2017
sanjithBPS:
complete wrong
Answered by
4
Answer:No it is not a term of the series
Step-by-step explanation:Because
a =9 ( first term)
d = 4 (common difference (second term - first term))
Tn = a+(n-1)d. [Formula]
503 = 9 +(n-1)4
503 = 9+4n- 4
503=4n+5
503-5=4n
498/4 =n
n =124.5
If we get n=0 for any sum then it is a term of the series else it is not.
☺
Similar questions