504 cones, each of diameter 3.5 cm and height 3 cm are melted and recast into a metallic sphere.find the diameter of the sphere and hence find its surface area. [ use π = 22/7]
Answers
Given that,
Diameter of cone = 3.5 cm = 7/2 cm
So, radius of cone, r = 7/4 cm
Height of cone, h = 3 cm
We know, Volume of cone of radius r and height h is given by
So, using this result, we have
So,
Now, it is given that,
504 cones, each of diameter 3.5 cm and height 3 cm are melted and recast into a metallic sphere.
Let assume that radius of sphere be R cm.
So, as 504 cones melted and recast in to a metallic sphere.
Hence,
Now,
Additional Information
⚘Solution:-
Volume of 504 cone=Volume of Sphere
⇢504×××××3=π
=1157.625
⇢
Diameter of Sphere=2×r=
=4××10.5
⇢
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✰Surface area of cuboid=2(lb+bh+hl)
✰Surface area of cube=
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✰Total surface area of cylinder=
✰Curved surface area of cone=×l×=
✰Total surface area of cone==πr(l+r)
✰Surface area of sphere=
✰Volume of cube=
✰Volume of Hemisphere=