504 cones, each of diameter 3.5 cm and height 3 cm are melted and recast into a metallic sphere. Find the diameter og the sphere and it's surface area
ManasMonga:
multiply no. of cones with volume of 1 cone and put it equal to volume of a sphere....... uh will get your solution....
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volume of 504 cones =volume of sphere
504(1/3× 22/7 × 3.5/2 × 3.5/2 × 3)=22/7×r^3
3 and 3 gets cancel 4 divides 504
126×12.25=r^3
1543.5=r^3
11.55=r
diameter is 23.10cm
now T.S.A of sphere =3×22/7×11.55×11.55
= 1257.75cm^2
hope this answer is helpful plz mark it as brainliest
504(1/3× 22/7 × 3.5/2 × 3.5/2 × 3)=22/7×r^3
3 and 3 gets cancel 4 divides 504
126×12.25=r^3
1543.5=r^3
11.55=r
diameter is 23.10cm
now T.S.A of sphere =3×22/7×11.55×11.55
= 1257.75cm^2
hope this answer is helpful plz mark it as brainliest
Answered by
1
PLZZZ MARK IT AS BRAINLIEST..
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