(50a +10b =20) + (30a - 10b = -4)
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Answer:
Solve by Substitution :
// Solve equation [2] for the variable a
[2] 30a = 10b + 200
[2] a = b/3 + 20/3
// Plug this in for variable a in equation [1]
[1] 50•(b /3+20/3) + 40b = 500
[1] 170b/3 = 500/3
[1] 170b = 500
// Solve equation [1] for the variable b
[1] 170b = 500
[1] b = 50/17
// By now we know this much :
a = b/3+20/3
b = 50/17
// Use the b value to solve for a
a = (/3)(50/17)+20/3 = 130/17
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