Question

50cc of decinormal NaOH solution will be complete neutralised by 'x' ml of drcimolar H2So4 Solution.the value of x is ​

Answer 1

Explanation:

molecular mass of NaOH = 40 g

molarity of stock solution = 40×5002×1000 = 0.1 M

no. of moles of NaOH in 40.50 ml of solution = 0.1×100040.5 = 0.004504 moles

for neutralisation, we have: no. of moles of HCl = no. of moles of NaOH

1 decimolar = 0.1 M

so, number of moles of HCl in 10 ml decimolar solution = 100010×0.1 = 0.001

number of moles of HCl in 20 ml decimolar solution = 100020×0.1 = 0.002

number of moles of HCl in 50 ml decimolar solution = 100050×0.1 = 0.005