50cc of N/100 HCl neutralized 42 cc of No2CO3. How nich to water must be added to 1 liter solution of Na2CO3 to make it exacly N/10??
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Correct option is
D
490 ml
Let normality of H
2
SO
4
=N
N
1
V
1
=N
2
V
2
⇒0.1×22.7=N×10.2
⇒N=0.2225
Now the number of equivalent present in
400ml solution= N×400
=0.2225×400=89meq
For making the solution of 0.1N, Let V ml of solution is needed
⇒0.1×V=89
V=890ml
Hence the volume of water that must be added is 400ml
∴V=890−400=490ml
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