50g CaCo3 is allowed to dissociate in 22.4lit vessel at 819 degree centigrade .if 50% of CaCo3 is left at equilibrium , active masses of CaCo3 ,CaO &CO2 respectively are
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Answer: active mass of caco3 is 1
Active mass of cao is 1
But active mass of co2 is 0.25/22.4
Explanation:
Active mass of solids is taken as unity
For co2 -at starting 0.5 mole is present by stoichiometry we know half mole will dissociate to form half mole of co2 but dissociation is only 50% so .25 moles will be formed
And active mass is no of moles per litre(molarity)
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