Question

50g CaCO3 is allowed to dissociated in
22.4 lit vessel at 819°C. If 50% of CaCO3 is left at
equilibrium, active masses of CaCO3, CaO and
CO, resepectively are
1) 25g ; 14 g ; 1/22.4 mol/lit
2) 1; 1; 1/89.6 mol/lit
3) 25 ; 14; 1/89.6 mol/lit
4)1;1;1​

Answer 1

Answer:

Volume of vessel=22.4L

$CaCO_{3} ---->CaO+CO_{2}$

t=0 50g or

50/100=0.5moles

t=eqbm  0.25 moles       0.25 moles    0.25 moles

active mass : CO2 = 0.25 / 22.4 = 0.011 mol L-1

so option 3 is correct