Question

50g CaCO3 is present in 200ml water. If density of solution is 1.2 gml-1. Calculate the morality of the solution.

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Answer 1

Answer:

morality = no of mole / volume in liters

no of moles = mass given / molar mass

= 50 / 100 = 0.5 moles

density = mass / volume

1.2g ml-1 = 50 / vol

vol = 50 / 1.2

= 41.66

morality = 0.5/41.66

= 0.012 M

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