Question

50g h2 and 50 g o2 react to form h20.which is the limiting reagent? what amount of water formed?​

Answer 1

Answer:

80g of h2 are reacted with 80g of o2 to form water find out the mass of water obtained which substance is the limiting reagent

Answer 2

Answer:

mass of water formed and the limiting reagent?

Mass of O2 =50gm ,Mass of H2 =50gm

Molecular weight of O2= 32gm

Molecular weight of H2=2gm

Moles of H2 = 50/2=25

Moles of O2= 50/32=1.5

Here Oxygen is limiting reagent due to less moles available for reaction for 1.5 moles

Reaction of water formation

H2(10gm) + 1/2 O2(50gm) = H2O (60gm)

Formation of water by 5 molecule of H2 and 1.5 molecule of O2 therefore 5 molecule of H2 is 10gm and 1.5 molecule of O2 is 50gm form by summation is 60gm of H2O molecule.

mass of water formed and the limiting reagent?

Mass of O2 =80gm ,Mass of H2 =80gm

Molecular weight of O2= 32gm

Molecular weight of H2=2gm

Moles of H2 = 80/2=40

Moles of O2= 80/32=2.5

Here Oxygen is limiting reagent due to less moles available for reaction for 2.5 moles O2 required 5 moles of H2

Reaction of water formation

H2(10gm) + 1/2 O2(80gm) = H2O (90gm)

Formation of water by 5 molecule of H2 and 2.5 molecule of O2 therefore 5 molecule of H2 is 10gm and 2.5 molecule of O2 is 80gm form by summation is 90gm of H2O molecule.