50g of 10% lead nitrate is mixed with 50g of 10% sodium chloride in a closed vessel. after sometime 6.83g of lead chloride was precipitated. Besides, the reaction mixture contained 90g of water and sodium nitrate. what is the amount of sodium nitrate formed? ....... pls answer fast ...... question from class 9 atoms and molecules
Answers
Answered by
16
119g of NaCl produce= 170 of NaNO3
1g of NaCl produce= 170/119 of NaNO3
so 5g of NaCl produce= 170/119 x 5
=7.143g of NaNO3
1g of NaCl produce= 170/119 of NaNO3
so 5g of NaCl produce= 170/119 x 5
=7.143g of NaNO3
Answered by
6
Explanation:
7.143g of NaNO3
7.143g of NaNO3hope you GET it
Similar questions