Question

50g of a metal piece at 27°C requires 2400J of heat energy to attain temperature of 327°C. calculate the specific heat capacity of the metal.

URGENT!!​

Answer 1

Answer:

your answer is 0.16

Explanation:

Given: m=50g;△t=327

C−27

∘

C=300

∘

C,Q=2400 J

Now, Q=mc△t

2400=50×C×300

Specific heat capacity of the metal, c=

50×300

2400

=0.16 J/g

∘

C

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Answer 2

This is the answer of your question