50g of calcium carbonate on heating gave 26g of calcium oxide and 24g of
CO2.Show that these observations are in agreement with the law of
conservation of mass
Answers
Given:-
→ Mass of Calcium carbonate reacted = 50g
→ Mass of Calcium Oxide formed = 26g
→ Mass of Carbon Dioxide formed = 24g
To show:-
→ The above observations are in agreement with 'Law of Conservation of mass'.
Solution:-
The balanced chemical equation for the reaction is :-
CaCO₃ → CaO + CO₂
In the above equation, 'reactant' is :-
• Calcium Carbonate [CaCO₃]
In the above equation,' products' are :-
• Calcium Oxide [CaO]
• Carbon dioxide [CO₂]
________________________________
Now, according to 'Law of Conservation of mass', we know that :-
Mass of reactants = Mass of products
⇒Mass(CaCO₃) = Mass(CaO) + Mass(CO₂)
⇒50g = 26g + 24g
∴ 50g = 50g
Since we have proved that mass of reactants and products are equal. Thus, the above observations are in agreement with 'Law of Conservation of mass'.
The law of conservation of mass by Lavoisier states that, mass can neither be created or destroyed in a chemical reaction.
Before reaction:-
Mass = 50 g ()
After reaction:-
Mass = 24 g + 26 g ()
⇒ Mass = 50 g.
∴ Mass before reaction = Mass after reaction.
Or, this reaction is in agreement with the law of conservation of mass.
More:-
There is another law which governs chemistry. That is, the law of constant or definite proportions.
It states that,
“The number of elements in a given compound is constant in ratio by mass.”
It was given by Joseph L. Proust.