50g of calcium carbonate on heating gave 26g of calcium oxide and 24g of CO2.Show that these observations are in agreement with the law of conservation of mass.
Answers
Amount of reactants (50 g of CaCO3) = Amount of products (26 g CaO + 24 g CO2)
This agrees with law of conservation of mass
★QuestioN :
✳50g of calcium carbonate on heating gave 26g of calcium oxide and 24g of CO2.Show that these observations are in agreement with the law of conservation of mass.
✦GiveN :
➫ Mass of Calcium carbonate reacted = 50g
➫ Mass of Calcium Oxide formed = 26g
➫ Mass of Carbon Dioxide formed = 24g
✦To FiNd :
➫ The above observations are in agreement with 'Law of Conservation of mass'.
★SolutioN :
The balanced chemical equation for the reaction is :-
CaCO₃ → CaO + CO₂
In the above equation, 'reactant' is :-
• Calcium Carbonate [CaCO₃]
In the above equation,' products' are :-
• Calcium Oxide [CaO]
• Carbon dioxide [CO₂]
________________________________
Now, according to 'Law of Conservation of mass', we know that :-
Mass of reactants = Mass of products
⇒Mass(CaCO₃) = Mass(CaO) + Mass(CO₂)
⇒50g = 26g + 24g
∴ 50g = 50g
❖ Since we have proved that mass of reactants and products are equal. Thus, the above observations are in agreement with 'Law of Conservation of mass'.