Question

50g of ice at 0 degree celsius is mixed with 50g of water at 80 degree celsius the final temperature is

Answer 1

The final temperature is 0°C.

Explanation:

we have 50g of ice at 0°C mixed with 50g of water at 80°C.

• since, the ice is at lower temperature, it gains heat from water and water loses a part of its energy.
• We have , heat lost by water = Heat gained by Ice
• Let T be the final temperature attained.
• initially, 50g ice will melt into water, the heat gained here is latent heat of fusion of water= $mL= 50*80$=4000 calories(change of state)
• The 50g water at 80°C looses 4000 calories to reach the temperature t.

$4000=ms(80-t)$

⇒$4000= 50*1*(80-t)\\ t=0$

Therefore, the entire water ice fusion has come to water at 0°C.