Question

50g of oil of specific heat capacity 2.2 jg'-1°C'-1 is cooled from 350℃ to 25℃. Calculate the heat energy given out by the oil.​

Answer 1

Answer:

Given , m=400g,θ

1

=100

0

C,θ

2

=? , specific heat of vegetable oil c=1.98J/g−

o

C,Q=47376J

Now , by the definition of specific heat c ,

Q=mcΔθ=mc(θ

1

−θ

2

)

or 47376=400×1.98(100−θ

2

)

or (100−θ

2

)=47376/(400×1.98)=59.8

or θ

2

=100−59.8=40.2

o

C