Question

50gm of calcium carbonate is treated excess hydro chloric acid calculate the volume and number of molecules if carbon dioxide liberal in this reaction​

Answer 1

Molar mass of CaCO3 = 100 g

number of moles of CaCo3 = 50/100 =0.5 moles

$\sf \: CaCO_3 + HCl \rightarrow CaCl_2 +CO_2+H_2O$

$1 \: mole \: of \: CaCO_3 \rightarrow \: 1 \: mole \: ofCO_2$

$0.5 \: m \: CaCO_3 \rightarrow0.5 \: m \: CO_2$

$no. \: of \: molecules = n_{moles} \times n_a$

$= 0.5 \times 6.022 \times {10}^{23}$

$\boxed { \bold{ 3.011 \times {10}^{23} \: molecules}}$