50gram nitrogen 8gram hydrogen are combined to produce ammonice which is limiting regent.calcuate amount of nh3 in this reaction
Answers
Answer:
answer is 56.67 kg.
Explanation:
N2+3H2 ⟶2NH3
Molecular mass of Nitrogen =28g/mol=0.028kg/mol
Molecular mass of Hydrogen =6g/mol=0.006kg/mol
Molecular mass of Ammonia =17g/mol=0.017kg/mol
Now, according to the balanced chemical equation,
0.028 kg of Nitrogen reacts with 0.006 kg of Hydrogen.
∴ 50 kg of Nitrogen reacts with
[ 0.028)(0.006×50) ]=10.71kg of Hydrogen.
The amount of Hydrogen (given 10 kg) is less than the amount required (i.e., 10.71 kg) for 50 kg of Nitrogen.
Therefore, Hydrogen is the limiting reagent.
Hence, the formation of Ammonia will depend on the amount of Hydrogen available for reaction.
∵ Amount of ammonia produced by 0.006 kg of hydrogen =2×0.017=0.034kg
∴ Amount of ammonia produced by 10 kg of Hydrogen =
0.006
0.034×10
=56.67kg
Hence, 56.67 kg of ammonia gas will be formed and hydrogen will be limiting reagent.
Answer:
tq
Explanation:
