Question

50kg of Nitrogen and 10kg hydrogen are mixed to produce ammonia.Calculate the ammonia formed.Identify the limiting reagent in the production of the ammonia in this reaction​

Answer 1

Explanation:

N2+3H2---> 2NH3

mol of N2=50000/28=1785.71mol

mols of H2=10000/2=5000 mol

since 3 mols of H2 reacts with 1 mol of N2 to form 2mols of NH3

hence 5000 mols of H2 will react with 5000/3=1666.66 mols of N2 to form 5000×2/3=3333.33 mols of NH3

=3333.33x17=56666.66gm NH3=56.66 kg