50kg of nitrogen reacts with 10 kg of hydrogen how much ammonia is formed
Answers
Answered by
1
50 kg N2 corresponds to 1.8 kmoles
10 kg H2 corresponds to 5 kmoles
N2+3H2=2NH3
For 1 kmole of N2 we require 3 kmoles of H2
Thus for 1.8 kmoles of N2 we require 1.8*3 = 5.4 kmoles of H2.
But we have only 5kmoles, thus H2 is limiting reagent.
3 kmoles of H2 gives 2 kmoles of NH3
thus 5 kmoles will give 2*5/3 =10/3 =3.33 kmoles
Thus amount of ammonia formed is 3.33*17 = 56.61 kg
10 kg H2 corresponds to 5 kmoles
N2+3H2=2NH3
For 1 kmole of N2 we require 3 kmoles of H2
Thus for 1.8 kmoles of N2 we require 1.8*3 = 5.4 kmoles of H2.
But we have only 5kmoles, thus H2 is limiting reagent.
3 kmoles of H2 gives 2 kmoles of NH3
thus 5 kmoles will give 2*5/3 =10/3 =3.33 kmoles
Thus amount of ammonia formed is 3.33*17 = 56.61 kg
Similar questions