Question

50ml of 0.001 N HCL and 10ml of 0.01N H2so4 are mixed together ,calculate p.H of resulting solution​

Answer 1

Answer:

Given = volume = 50ml 0.001 N HCL and 10ml of 0.01N H2so4 are mixed together

to find  = P.H of resulting solution

solution =   1st  find the miliequivalents of HCl = N x V(ml)

             =   0.001 x 50

             =   0.05

now, miliequivalents of H2SO4 = N X V(ml)

                                                   = 0.01 x 10

                                                  =  0.1

add both the miliequivalents of acids = 0.05 +b 0.1 = 0.15

now,      N =  0.15 / 60 = [H⁺]

          P.H = log1/ [H⁺]  = log 60/ 0.15

          P.H = 2.6

p.H of resulting solution​  is 2.6.

             

Answer 2

Answer:

PH is 2.6

Explanation:

thank me later