Question

50ml of 0.1M HCl is mixed with 50ml of 0.05M H2SO4, then the resultant [Cl-] in the solution is:

1) 0.05M

2) 0.025M

3) 0.1M

4) 0.5M

Answer 1

answer : option (1) is correct.

explanation : 50ml of 0.1M HCl is mixed with 50ml of 0.05M H2SO4.

we see, 1 mole of HCl contains one mole of chlorine ions.

mole of HCl = concentration of HCl × volume

= 0.1 × 50 = 5 milimole

so, number of mole of [Cl-] ions = 5 milimole

now,

concentration of [Cl-] ions = number of mole /volume

= 5 milimole/(50 + 50)ml

= 5/100

= 0.05M

hence, concentration of [Cl-] ion = 0.05M