50ml of 0.2N H2SO4 were added to 100ml of
0.2N HNO3. Then the solution is diluted to
300ml. The pH of resultant solution is
(A) 1
(B) 4
(C) 6
(D) 4.8
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SOLUTION:
Resulting normality =
(N1 V1 +N2 V2+ N3 V3 ) / V1 + V2+ V3
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