Question

50ml of 0.2N K Cr O 2 27 is required to oxidise
40 ml FeSO4 solution in acidic medium. The
weight of iron present per lit

Answer 1

Answer:

Explanation:

equivalent of k2cr2o7 = 10

equivalent of feso4=equivalent of k2cr2o7

moles*2000=10

moles=0.005

w/152=0.005

w=0.076 gm

152  feso4 contains 56 gm fe

0.076 gm feso4 contain 0.028 gm fe

40 ml contain 0.028 gm fe

1000ml contain 0.7 gm fe

therefore weight of fe per lt = 0.7 gm